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Author SHA1 Message Date
iris-ai 25e456e0b5 Say what the fuzzers can no longer tell about the stale-answer guard
Dropping `dirty_size_under` from it now passes every run there is. It stays
for the one entry the bottom-up ordering does not reach -- `update` draws
the root for a resize before `redraw_updates` runs -- which is a hole
reasoned rather than measured, and the note says which.
2026-09-17 05:12:44 -04:00
iris-ai 53b00c68e9 Find a span's leftover boundary through the inverse it already has
The decision used a rounded division, `total.px.div(fixed)`, where the room
the children get is a floored multiply, so the boundary and the drawing it
guards were two expressions for one length and disagreed at the edge of it.
`room` is that length as a `Len`, `room.to_px` is the multiply, and
`Holds::through` is its exact preimage -- so ask `room` whether anything is
left and hand the answer back through the same expression.

The three branches go with the division. They were the sign of `1 - rel`:
the fixed parts growing slower than the box, faster, or exactly with it, and
`through` reads that sign already. Forty lines become twelve, one `div`
leaves layout, and the boundary is the drawing's own.

Green on the suite, the shrinker at 400 seeds of depth 5, the oracle at 1000
seeds of depth 6 and 120 in debug, and 2000 seeds at depth 4 over all
fifteen cases. `tabs`, `view`, `minimal` and `random` byte-identical.
2026-09-17 05:02:45 -04:00
2 changed files with 24 additions and 34 deletions

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+8
View File
@@ -202,6 +202,14 @@ impl UiRenderState {
// that marks a reader is in `redraw`, which is not what asked here. // that marks a reader is in `redraw`, which is not what asked here.
// Both retained routes are an answer, so the question is asked once // Both retained routes are an answer, so the question is asked once
// rather than by each of them. // rather than by each of them.
//
// Since `a92c6ac` settles a frame strictly bottom-up, no fuzzer can
// tell whether the second half of this still does anything: dropping
// `dirty_size_under` passes the suite, the shrinker at 400 seeds of
// depth 5, the oracle at 1000 of depth 6 and 2000 seeds at depth 4.
// It stays because `update` draws the root for a resize before
// `redraw_updates` runs at all, which that ordering does not reach --
// a hole that is reasoned rather than measured.
let stale = let stale =
rsc.widgets().needs_redraw.contains(&id) || self.dirty_size_under(id, rsc.widgets()); rsc.widgets().needs_redraw.contains(&id) || self.dirty_size_under(id, rsc.widgets());
let replace_answer = self.answer_invalid.remove(&id) || (self.replace_answers && stale); let replace_answer = self.answer_invalid.remove(&id) || (self.replace_answers && stale);
+16 -34
View File
@@ -46,43 +46,26 @@ impl Widget for Span {
|sum, len| sum + *len, |sum, len| sum + *len,
); );
// What is left for the shares to divide: the box less everything
// fixed, as a length of the box rather than a number of pixels.
let room = Len::rel_max() - Len::from_parts(total.rel, total.px);
// Whether anything is left over is a question in pixels: `rel(0.5)` // Whether anything is left over is a question in pixels: `rel(0.5)`
// beside 300 px is full at 600 and overfull at 400. The room to // beside 300 px is full at 600 and overfull at 400. Asked of `room`
// divide is `len * fixed - total.px`, and the length where it runs // itself, and answered back through the same expression, so the
// out is exactly the box a parent sizing itself from this answer // boundary is the drawing's own and not a second way of finding it:
// hands back -- which is why this used to need a margin either side // the three cases a rounded division needed -- the fixed parts
// of the boundary, and why it does not now: that box and this sum are // growing slower than the box, faster, or exactly with it -- are the
// whole counts of the same step, and both routes to it land on the // sign of `room.rel`, which `through` already reads. What the
// same count. What the generated oracle checks is the consequence, // generated oracle checks is the consequence, since which children
// since which children exist at all turns on this. // exist at all turns on this.
let fixed = Rel::ONE - total.rel;
let mut shares = false; let mut shares = false;
if total.leftover > Weight::ZERO { if total.leftover > Weight::ZERO {
let current = painter.px_len(axis); shares = room.to_px(painter.px_len(axis)) > Px::ZERO;
let holds = if fixed > Rel::ZERO { let holds = match shares {
// The box length the fixed parts alone fill. true => Holds::from(Px::STEP..=Px::MAX),
let full = total.px.div(fixed); false => Holds::from(Px::MIN..=Px::ZERO),
shares = current > full;
match shares {
true => Holds::from(full.next_up()..=Px::MAX),
false => Holds::from(Px::MIN..=full),
}
} else if fixed < Rel::ZERO {
// The relative parts grow faster than the box does, so here
// a shorter box is the one that leaves room.
let full = total.px.div(fixed);
shares = current < full;
match shares {
true => Holds::from(Px::MIN..=full.next_down()),
false => Holds::from(full..=Px::MAX),
}
} else {
// The relative parts take exactly the box, whatever it is, so
// the only room is what negative pixels leave.
shares = total.px < Px::ZERO;
Holds::ANY
}; };
painter.holds(axis, holds); painter.holds(axis, holds.through(room));
} }
// Across itself a span is as long as its longest child -- unless a // Across itself a span is as long as its longest child -- unless a
@@ -99,7 +82,6 @@ impl Widget for Span {
// row. // row.
let mut fixed = Len::rel_min(); let mut fixed = Len::rel_min();
let mut taken = Weight::ZERO; let mut taken = Weight::ZERO;
let room = Len::rel_max() - Len::from_parts(total.rel, total.px);
let mut start = Len::rel_min(); let mut start = Len::rel_min();
let mut ortho = LayoutLen::ZERO; let mut ortho = LayoutLen::ZERO;
for (child, len) in self.children.iter().zip(&lens) { for (child, len) in self.children.iter().zip(&lens) {